Javascript URL Api
The URL interface is used to parse, generate, normalize and encode URLs.
It helps you to easily read and edit the components of a URL.
Use of
We generate the current URL using the URL()
api.
const url = new URL('http://phpexample.net:80/search?q=test1#test2')
now we can access some properties under the url
variable.
hash
-> returns if there is a value ending with #
. The result in our example;
console.log(url.hash);
// #test2
host
-> returns the domain name along with the port. The result in our example;
console.log(url.host);
// phpexample.net:80
hostname
-> returns the domain name. The result in our example;
console.log(url.hostname);
// phpexample.net
href
-> returns the entire current url. The result in our example;
console.log(url.href);
// http://phpexample.net:80/search?q=test1#test2
origin
-> returns domain and port with schema. The result in our example;
console.log(url.origin);
// https://phpexample.net:80
pathname
-> returns the characters after /. This excludes query strings and fragments. The output in our example is;
console.log(url.pathname);
// /search
port
-> returns the port. The result in our example;
console.log(url.port);
// 80
protocol
-> returns the protocol of the url. The result in our example;
console.log(url.protocol);
// http:
search
-> returns query strings, that is, the ones after the question mark. The result in our example;
console.log(url.search);
// ?q=test1
searchParams
-> returns a URLSearchParams object, so you can get or add query strings with methods like get() and set(). The output in our example is;
console.log(url.searchParams.get('q'));
// test
url.searchParams.set('type', '3')
console.log(url.href);
// https://phpexample.net:80/search?q=test1&type=3#test2
You can also do URL validation.
try {
new URL('is this url correct, i don't think so?')
} catch (e) {
console.log(e)
// TypeError: Failed to construct 'URL': Invalid URL
}
It's pretty easy to manipulate URLs. If I wanted to change our example url to phpexample.net;
url.hostname = 'phpexample.net';
url.protocol = 'http'
console.log(url.href);
// http:/phpexample.net/search?q=test1&type=3#test2
That's it, see you in the next lesson :)
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